                       RELATED ARTICLES                 # Multiplication Table - Vedic Mathematics' Simple Technique Helps in Remembering It Easily

By using a simple technique from Vedic Math, I help you to remember Multiplication Table. You need to just remember some basic multiplication facts (2 times table upto 8 x 2; 3 times table upto 7 x 3; 4 times table upto 6 x 4; 5 times table upto 5 x 5;). Using these basic multiplication facts, we can arrive at all other values.The method is easy to follow, learn and apply.

To remember Multiplication Table, consider the sum of multiplicand and multiplier.

Remember the values for the sum < 10 (2 times table upto 8 x 2; 3 times table upto 7 x 3; 4 times table upto 6 x 4; 5 times table upto 5 x 5;).

We may call these basic Multiplication facts to be remembered.

Using these basic Multiplication facts, We arrive at the values for the sum > 10 (all other values of the multiplication Table) using simple technique from Vedic Mathematics.

The method we follow, here, is very simple to understand and very easy to follow.

The method is based on "Nikhilam" sutra of vedic mathematics.

The method will be clear from the following examples.

Example 1 :

Suppose, we have to find 9 x 6.

First we write one below the other.

9

6

Then we subtract the digits from 10 and write the values (10-9=1; 10-6=4) to the right of the digits with a '-' sign in between.

9 - 1

6 - 4

The product has two parts. The first part is the cross difference (here it is 9 - 4 = 6 - 1 = 5).

The second part is the vertical product of the right digits (here it is 1 x 4 = 4).

We write the two parts seperated by a slash.

9 - 1

6 - 4

-----

5/4

-----

So, 9 x 6 = 54.

Let us see one more example.

Example 2 :

Suppose, we have to find 8 x 7.

First we write one below the other.

8

7

Then we subtract the digits from 10 and write the values (10-8=2; 10-7=3) to the right of the digits with a '-' sign in between.

8 - 2

7 - 3

The product has two parts. The first part is the cross difference (here it is 8 - 3 = 7 - 2 = 5).

The second part is the vertical product of the right digits (here it is 2 x 3 = 6).

We write the two parts seperated by a slash.

8 - 2

7 - 3

-----

5/6

-----

So, 8 x 7 = 56.

Let us see one more example.

Example 3 :

Suppose, we have to find 9 x 9.

First we write one below the other.

9

9

Then we subtract the digits from 10 and write the values (10-9=1; 10-9=1) to the right of the digits with a '-' sign in between.

9 - 1

7 - 1

The product has two parts. The first part is the cross difference (here it is 9 - 1 = 9 - 1 = 8).

The second part is the vertical product of the right digits (here it is 1 x 1 = 1).

We write the two parts seperated by a slash.

9 - 1

9 - 1

-----

8/1

-----

So, 9 x 9 = 81.

In the next examples, the second part has two digits.

Let us see how to handle the issue.

Example 4:

To find 7 x 6

First we write one below the other.

7

6

Then we subtract the digits from 10 and write the values (10-7=3; 10-6=4) to the right of the digits with a '-' sign in between.

7 - 3

6 - 4

The product has two parts. The first part is the cross difference (here it is 7 - 4 = 6 - 3 = 3).

The second part is the vertical product of the right digits (here it is 3 x 4 = 12).

We write the two parts seperated by a slash.

7 - 3

6 - 4

-----

3/12

-----

The second part, here, has two digits.

we retain the units' digit (2) and carry over the other digit (1) to the left.

7 - 3

6 - 4

--------------

(3+1)/2 = 4/2

-------------

So, the answer becomes (3+1)/2 = 4/2

Thus, 7 x 6 = 42.

Example 5 :

To find 8 x 3

By following the above procedure, we may write as follows.

8 - 2

3 - 7

-----

2/14

-----

The first part = 8 - 7 = 3 - 2 = 1.

The second part here is 2x7 = 14.

It has two digits. we retain the units' digit (4) and carry over the other digit (1) to the left.

8 - 2

3 - 7

--------------

(1+1)/4 = 2/4

-------------

So, the answer becomes (1+1)/4 = 2/4

Thus, 8 x 3 = 24.

let us see one last example.

Example 6 :

To find 6 x 5

By following the above procedure, we may write as follows.

6 - 4

5 - 5

-----

1/20

-----

The first part = 6 - 5 = 5 - 4 = 1.

The second part here is 4x5 = 20.

It has two digits. we retain the units' digit (0) and carry over the other digit (2) to the left.

6 - 4

5 - 5

--------------

(1+2)/0 = 3/0

-------------

So, the answer becomes (1+2)/0 = 3/0

Thus, 6 x 5 = 30.

Thus, we can arrive at any values upto 10 x 10.

For multiplication of one and two digit numbers, go to ,

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# ABOUT THE AUTHOR

Name : kvln
Qualifications : B.Tech., M.S. (from IIT, Madras)
Has 14 years of teaching experience.
Love for math and love for teaching
makes me feel more than happy to help.
Has own math web site :
http://www.math-help-ace.com/

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